(1/x^2)+(7/x)+12=0

Solution for (1/x^2)+(7/x)+12=0 equation:

D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x+1/(x^2)+12 = 0

7*x^-1+x^-2+12 = 0

t_1 = x^-1

1*t_1^2+7*t_1^1+12 = 0

t_1^2+7*t_1+12 = 0

DELTA = 7^2-(1*4*12)

DELTA = 1

DELTA > 0

t_1 = (1^(1/2)-7)/(1*2) or t_1 = (-1^(1/2)-7)/(1*2)

t_1 = -3 or t_1 = -4

t_1 = -4

x^-1+4 = 0

1*x^-1 = -4 // : 1

x^-1 = -4

-1 < 0

1/(x^1) = -4 // * x^1

1 = -4*x^1 // : -4

-1/4 = x^1

x = -1/4

t_1 = -3

x^-1+3 = 0

1*x^-1 = -3 // : 1

x^-1 = -3

-1 < 0

1/(x^1) = -3 // * x^1

1 = -3*x^1 // : -3

-1/3 = x^1

x = -1/3

x in { -1/4, -1/3 }